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# Kinematicequations

Published on: Mar 3, 2016

#### Transcripts - Kinematicequations

• 1. BY NIYA WATKINS, SARAH GIMONT, AND JACKIE PFEIFFER Kinematic Equations
• 2. kinematic Equations <ul><li>1) V=a t +V o </li></ul><ul><li>2) X=½ a t 2 +V o t + X o </li></ul><ul><li>3) V 2 = v o 2 +2a(X-X o ) </li></ul><ul><li>4) X =½(V+V o ) t +X o </li></ul>
• 3. kinematics <ul><li>We have 6 variables when dealing with kinematic equations </li></ul><ul><ul><li>X, X o , V, V o , a, and t </li></ul></ul><ul><ul><li>however, when attempting to solve the equations, one variable will be omitted and one variable will be the unknown </li></ul></ul>
• 4. Kinematics <ul><li>Example problem: Niya pushes a ball down a ramp with a speed of 3 m/s. As the ball rolls, it loses speed at a rate of 5 m/s. </li></ul><ul><li>How far does the ball roll before it comes back up? </li></ul><ul><ul><li>.9 m </li></ul></ul>
• 5. kinematics <ul><li>Sample Problem: explanation </li></ul><ul><li>First, we must figure out which variables we have </li></ul><ul><ul><li>we know V o =3(the starting speed), that V o =0(the starting point), X=?(how far...), and a=-5(the rate the speed decreases at) </li></ul></ul><ul><ul><li>We now know we can use equation 3 </li></ul></ul><ul><ul><ul><li>0=9 + -10(x) </li></ul></ul></ul>
• 6. free fall <ul><li>A special case of constant acceleration. </li></ul><ul><li>Secrets: </li></ul><ul><ul><li>Acceleration is -9.8 m/s 2 </li></ul></ul><ul><ul><li>Stop at the top </li></ul></ul><ul><ul><li>Symmetry (time up = time down) </li></ul></ul>
• 7. free fall <ul><li>Example Problem: Sarah drops a ball off a building that it 200m tall. </li></ul><ul><li>How long does it take it to fall halfway? </li></ul><ul><ul><li>4.52s </li></ul></ul>
• 8. free fall <ul><li>Example Problem: Explanation </li></ul><ul><li>First, we must figure out which variables we have </li></ul><ul><ul><li>We know X o =0(the origin), X=200(the height of the building), V o =0(the ball is dropped), a=-9.8(rule of free fall), and t=?(how long…) </li></ul></ul><ul><li>So we would use equation 2 </li></ul><ul><ul><li>200=-4.9t 2* </li></ul></ul><ul><ul><li>* remember we need to have a real answer </li></ul></ul>