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# Populationgrowth

Published on: Mar 4, 2016
Published in: Travel      Technology

#### Transcripts - Populationgrowth

• 1. EXPONENTS and LOGARITHMS
• 2. In year 2005, the population of Jamaica was 2100284, and was increasing at rate of 0.95% per year.
• 3. Write an equation to represent the population of Jamaica as a function of number of years, y since 2005..
• 4. Population of Jamaica P = Po (1+ ) yn P = 2100284 ( 1 + 0.0095)y P = 2100284 ( 1.0095)y Where as: Increasing rate P - amount of resulting population Po- principle or original amount r - percent rate y - time in years n – number of times the principle is *Given the equation of compounded per year population growth, you just have to plug in the values
• 5. For the population of Jamaica to double, how many years would it take?
• 6. P = 2100284 ( 1.0095)y 2(2100284) = 2100284 ( 1.0095)y 2 = 1.0095y Use the equation we got from the first question ln2 = yln(1.0095) y = ln(2) *It was stated that the resulting amount (P) ln(1.0095) should be doubled, so we multiply 2 to the original amount y 73.3039 *Then we just solve for (y) – the time in years it will take to double
• 7. Calculate when the population will reach 3000000.
• 8. P = 2100284 ( 1.0095)y 3000000 = 2100284 ( 1.0095)y 3000000 = 2100284 ( 1.0095)y 2100284 2100284 ln (1.4284) = lny(1.0095) *This question is just the same as the previous one. y = ln(1.4284) ln(1.0095) *We just put 3000000 as the final value instead. y 37.71